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目录
Donot字符串解密脚本

Donot新样本字符串解密,和以前的异或有一点不同

python
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key = "\"!AaBb#Cc$Dd%Ee&Ff'Gg(Hh)Ii*Jj+Kk,Ll-Mm.Nn/Oo0Pp1Qq2Rr3Ss4Tt5Uu6Vv7Ww8Xx9Yy:Zz;[{<|=]}> ^~?\_@`"
while(1):
EString = ""
DString = input("Input Decoded String: ")
for i in range(0,len(DString)):
addkey = key.find(DString[i])
if (addkey > 0x1F):
Fkey = addkey
else:
Fkey = addkey + 0x5F
EString = EString+chr(Fkey)
print(EString)

文章作者: Yenn_
文章链接: https://0xdf1001f.github.io/2021/08/20/Donot%E5%AD%97%E7%AC%A6%E4%B8%B2%E8%A7%A3%E5%AF%86%E8%84%9A%E6%9C%AC/
版权声明: 本博客所有文章除特别声明外,均采用 CC BY-NC-SA 4.0 许可协议。转载请注明来自 Wei's Blog

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